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The time needed for college students to complete a certain paper-and-pencil maze follows a normal distribution...

The time needed for college students to complete a certain paper-and-pencil maze follows a normal distribution with a mean of µ = 30 seconds and a standard deviation of σ = 3 seconds.   Nine randomly selected college students complete the maze.   The sampling distribution of the sample mean X it takes the sampled students to complete the maze is

  • A. normal with mean 30 and standard deviation 3.
  • B. normal with mean 30 and standard deviation 1.
  • C. negatively skewed and bimodal with mean 30 and standard deviation 1.
  • D. binomial with mean 30 and standard deviation 1.
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Answer: (B) normal with mean 30 and standard deviation 1.

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