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Two particles A and B start from rest at x = 0 and move along parallel...

Two particles A and B start from rest at x = 0 and move along parallel paths according to xA = 0.38 sin(πt/4) and xB = 0.20t , where xA and xB are in meters and t is in seconds counted from the start. Determine the time t (where t > 0 ) when both particles have the same displacement and calculate this displacement x.

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Answer #1

GIven the displacements of the two particles

And the condition that the displacements of the two particles are equal at a particular time t, then
  
  
And by solving this transcendental equation by using the graphical method, we get
  
The solution of this equation is when the two curves intersect each other. And this intersecting point is at
  
This is the time at which the displacements of the two particles become the same.
And the displacement at that time is
  
  

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