Two particles A and B start from rest at x = 0 and move along parallel paths according to xA = 0.38 sin(πt/4) and xB = 0.20t , where xA and xB are in meters and t is in seconds counted from the start. Determine the time t (where t > 0 ) when both particles have the same displacement and calculate this displacement x.
please help
GIven the displacements of the two particles
And the condition that the displacements of the two particles are
equal at a particular time t, then
And by solving this transcendental equation by using the graphical
method, we get
The solution of this equation is when the two curves intersect each
other. And this intersecting point is at
This is the time at which the displacements of the two particles
become the same.
And the displacement at that time is
Two particles A and B start from rest at x = 0 and move along parallel...
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