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Two particles move along an x axis. The position of particle 1 is given by x...

Two particles move along an x axis. The position of particle 1 is given by x = 6.00t2 + 4.00t + 5.00 (in meters and seconds); the acceleration of particle 2 is given by a = -9.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 21.0 m/s. When the velocities of the particles match, what is their velocity?

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Answer #1

stPaulicle d(x) 124 y acelera lion aう12 La 2 nd pay liele accale nation a= -96 -SEC Neloct c= 21 Veloi - 21-4S s 1.023 Sec Velch v 112(1.23) +u 16-24 с nykc ,

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