A particle moves along the x axis. Its position is given by the equation x = 1.5+ 2.5t -3.8t2 with x in meters and t in seconds.
(a) Determine its position when it changes direction
(b) Determine its velocity when it returns to the position it had at t =0? (Indicate the direction of the velocity with the sign of your answer.)
A particle moves along the x axis. Its position is given by the equatio
A particle moves along the x axis. Its position is given by the equation x = 1.8 + 2.5t − 3.8t2 with x in meters and t in seconds. (a) Determine its position when it changes direction. (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.) I have a) as 2.21m, i am having issues solving part (b).
A particle moves along the x axis. Its position is given by the equation x = 1.5 + 2.9t − 3.6t2 with x in meters and t in seconds. (a) Determine its position when it changes direction. m (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.) m/s
A particle moves along the x axis. Its position is given by the equation x = 2.1 + 2.7t − 3.5t2 with x in meters and t in seconds. (a) Determine its position when it changes direction. m (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.) m/s
Average and Instantaneous Velocity A particle moves along the x axis. Its position varies with time acording to the expression x =-4t + 2t2, where x is in meters and t is in seconds. The position-time graph for this motion is shown in the figure. Notice that the particle moves in the negative x direction for the first second of motion, is momentarily at rest at the moment t = 1 s, and moves in the positive x direction at times...
a particle moves along the x axis. its position as a function of time is given by x = 6.8 t + 8.5 t^2 , where t is in seconds and x is in meters. what is the acceleration as a function of time?
The position of a particle moving along an x axis is given by x = 12t2 - 2t3, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 3.0 s. Determine the average velocity of the particle between t = 0 and t = 3s.
Two particles move along an x axis. The position of particle 1 is given by x = 6.00t2 + 4.00t + 5.00 (in meters and seconds); the acceleration of particle 2 is given by a = -9.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 21.0 m/s. When the velocities of the particles match, what is their velocity?
Two particles move along an x axis. The position of particle 1 is given by x = 8.00t2 + 3.00t + 6.00 (in meters and seconds); the acceleration of particle 2 is given by a = -10.0t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 22.0 m/s. When the velocities of the particles match, what is their velocity?
A particle moves along the x axis according to the equation x = 2.06 + 2.95t - 1.0062, where x is in meters and t is in seconds. (a) Find the position of the particle at t = 2.80 s. m (b) Find its velocity at t = 2.80 s. m/s (c) Find its acceleration at t = 2.80 s. m/s2 Submit Answer
The position of a particle as it moves along the x axis is given for t > 0 by x = (t^3-3t^2+6t)m. Where is the particle when it achieves its minimum speed (after t = 0)?