a particle moves along the x axis. its position as a function of time is given by x = 6.8 t + 8.5 t^2 , where t is in seconds and x is in meters. what is the acceleration as a function of time?
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a particle moves along the x axis. its position as a function of time is given...
Constants| Periodic Table Part A A particle moves along the r axis. Its position as a function of time is given by z 6.8t +8.0t2 where t is in seconds and z is in meters. What is the acceleration as a function of time? Express your answer using two significant figures. m/s2 Submit Request Answer
A 5.60-kg particle moves along the x axis. Its position varies with time according to x = t + 4.0t3, where x is in meters and t is in seconds. (a) Find the kinetic energy of the particle at any time t. (Use the following as necessary: t.) K = (b) Find the magnitude of the acceleration of the particle and the force acting on it at time t. (Use the following as necessary: t.) a = F = (c)...
A particle moves along the x axis. Its position is given by the equation x = 1.5+ 2.5t -3.8t2 with x in meters and t in seconds. (a) Determine its position when it changes direction (b) Determine its velocity when it returns to the position it had at t =0? (Indicate the direction of the velocity with the sign of your answer.)
A particle moves along the x axis. Its position is given by the equation x = 1.5 + 2.9t − 3.6t2 with x in meters and t in seconds. (a) Determine its position when it changes direction. m (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.) m/s
A particle moves along the x axis. Its position is given by the equation x = 2.1 + 2.7t − 3.5t2 with x in meters and t in seconds. (a) Determine its position when it changes direction. m (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.) m/s
An object moves along the x-axis with its position x, in meters, given as a function of time t, in seconds, by x(-1.417-9.491+ 4.68 r(t)-1.41 t2-9.4% + 4.68 What is the object's velocity at time t 1.01 s? Number m/ s
A particle moves along the x axis. Its position is given by the equation x = 1.8 + 2.5t − 3.8t2 with x in meters and t in seconds. (a) Determine its position when it changes direction. (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.) I have a) as 2.21m, i am having issues solving part (b).
The position of a particle moving along an x axis is given by x = 12t^2 -2t^3, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 3.0s. (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached?
Q1 The position of a particle moving along an x axis is given by x = 1242 – 213, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 3 s. (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (1+2+1+1+1]
Average and Instantaneous Velocity A particle moves along the x axis. Its position varies with time acording to the expression x =-4t + 2t2, where x is in meters and t is in seconds. The position-time graph for this motion is shown in the figure. Notice that the particle moves in the negative x direction for the first second of motion, is momentarily at rest at the moment t = 1 s, and moves in the positive x direction at times...