if( i < 10) {
if( j < 10)
{ a = 0; }
else
{ a = 1;}
} else {
a = 2;
}
Convert the following c code into instructions MIPS Assembly language. Assume a associated with $s0, i...
Convert the high-level code into a MIPS-assembly program. Assume a is in $s0, b is in $s1, and c is in $s2. c = 0; while (a>0) { a = a-b; c++; }
Convert the following C fragment to equivalent MIPS assembly language. Assume that the variables a, b, c, d, i and x are assigened to registers $t1, $t2, $t3, $t4, $s0 and $s1 respectively. Assume that the base address of the array A and B is in register $a0 and $a1 respectively. if (a > 0) b = a + 10; else b = a - 10;
Translate the following C code to MIPS assembly code. Use a minimum number of instructions. Register allocations - i $s0 - j $s1 - base of A[] $s2 - base of B[] $s3 2) A[3] = B[i] + B[j]; 3) i = 0; while (j != A[i]) { i++; }
Convert the following MIPS instructions Into Machine Code Instructions. Assume the first Instruction starts at memory address 20000 slt $t1, $s1, $s0 beq $s1, $s2, L1 beq $t1, $zer0, L2 j Exit L1: add $s1, $s1, $s1 j Exit L2: add! $s1, $s1, 1 Exit:
B2. Convert the C code to MIPS assembly with only 2 efficient instructions: Register assignment: timer-v0 int timer = 0x0AC8 0001; B3. Write MIPS assembly code segment for the following C code snippet for (i - 0, i < 100; i++) -array Register assignment: i-) $ao Base of array -> $s0 array [ i+1] [i] / 2; B2. Convert the C code to MIPS assembly with only 2 efficient instructions: Register assignment: timer-v0 int timer = 0x0AC8 0001; B3. Write...
Convert the following C/C++ fragment into equivalent MIPS assembly language. Assume that the variables a, b, c, d, i and x are assigned to registers $t1, $t2, $t3, $t4, $s0 and $s1 respectively. if ((a<b && (c == 0) d = 1;
Convert the following high-level language into MIPS instructions. Please write comments for each instructions. Assume a, b, c, d are associated with registers $s0, $s1, $s2, $s3, respectively. void main () { int a = 10, b = 20; int c = add(a, b); int d = sub(a, b); swap (a, b); } int add( int var1, int var2) { return (var1 + var2); } int sub(int var1, int var2) { return (var1 - var2); } void swap(int var1, int...
Translate the following C code to MIPS assembly. Assume that the values of a, b, i, and j are in registers $s0, $s1, $t0, and $t1, respectively. Also assume that $s2 holds the base address of the array D. for (i = 0: i < a: i++) for (j = 0: j < b: j++) D[2 * j] = i + j;
Using beq only, not bge! Translate the following C code to MIPS assembly code. Use a minimum number of instructions. Assume that the values of a, b, i, and j are in registers $s0, $s1, $t0, and $t1, respectively. Also, assume that register $s2 holds the base address of the integer array D. Comments are required. for(i=1; i<a; i++) for(j=1; j<b; j++) D[2*j] = i + j;
Question 3 (10 points) Convert the following MIPS assembly code into machine language. Write the instruction in hexadecimal. The opcode for sw 43 (101011). sw St1, -4(St3) Question 4 (10 points) Consider the following MIPS assembly code: addi $s3, $0, 5 addi $s1, S0, 3 addi Ss1, $s1, 2 beq Ss3, Ssl, target addi Ss1, Ss1, 1 target: add Ss3, Ss1, Ssl a. After running the code, what is the value of Ss3? b. If the memory address of the...