Convert the high-level code into a MIPS-assembly program. Assume a is in $s0, b is in $s1, and c is in $s2.
c = 0;
while (a>0) {
a = a-b;
c++;
}
# c = 0; # while (a>0) { # a = a-b; # c++; # } # a is in $s0, b is in $s1, and c is in $s2 addi $s2, $zero, 0 # c = 0 while: ble $s0, $zero, end # while (a > 0) sub $s0, $s0, $s1 # a = a-b addi $s2, $s2, 1 # c++ j while end:
Convert the high-level code into a MIPS-assembly program. Assume a is in $s0, b is in...
Convert the following c code into instructions MIPS Assembly language. Assume a associated with $s0, i with $s1, and j with $s2. if( i < 10) { if( j < 10) { a = 0; } else { a = 1;} } else { a = 2; }
1.Please use 5-stage pipeline to describe following MIPS assembly code in non-forwarding pipeline. lw $s0, 0($t0) add $s1, $s0, $s0 mul $s2, $s1, $s0 . 2.Please use 5-stage pipeline to describe following MIPS assembly code in forwarding pipeline. lw $s0, 0($t0) add $s1, $s0, $s0 mul $s2, $s1, $s0 sw $s2, 4($t0)
Translate the following C code to MIPS assembly. Assume that the values of a, b, i, and j are in registers $s0, $s1, $t0, and $t1, respectively. Also assume that $s2 holds the base address of the array D. for (i = 0: i < a: i++) for (j = 0: j < b: j++) D[2 * j] = i + j;
Convert the following C/C++ fragment into equivalent MIPS assembly language. Assume that the variables a, b, c, d, i and x are assigned to registers $t1, $t2, $t3, $t4, $s0 and $s1 respectively. if ((a<b && (c == 0) d = 1;
1. Convert the following C statement to MIPS code. Assume x, y and z are assigned to registers $s0, $s1 and $s2 respectively and the starting address of array A is $s6. x = y + z + A[3] 2. 2.Convert the following C statement to MIPS code. Assume the base address of array A is $s3 and h is assigned to register $s2 . A[7] = h + A[7]
Convert the following C fragment to equivalent MIPS assembly language. Assume that the variables a, b, c, d, i and x are assigened to registers $t1, $t2, $t3, $t4, $s0 and $s1 respectively. Assume that the base address of the array A and B is in register $a0 and $a1 respectively. if (a > 0) b = a + 10; else b = a - 10;
Translate the following C code to MIPS assembly code. Use a minimum number of instructions. Register allocations - i $s0 - j $s1 - base of A[] $s2 - base of B[] $s3 2) A[3] = B[i] + B[j]; 3) i = 0; while (j != A[i]) { i++; }
1) Convert the following C code into MIPS assembly For (b-0; b<N, ++b) C-Z[b] If (Z[b]>W) W-Z[b] note: assign array Z, integers C and integer W to registers $SO, $S1, $S2 respectively. Put comments for each assembly line to explain its purpose.
Convert the following high-level language into MIPS instructions. Please write comments for each instructions. Assume a, b, c, d are associated with registers $s0, $s1, $s2, $s3, respectively. void main () { int a = 10, b = 20; int c = add(a, b); int d = sub(a, b); swap (a, b); } int add( int var1, int var2) { return (var1 + var2); } int sub(int var1, int var2) { return (var1 - var2); } void swap(int var1, int...
For the following C statement, what is the corresponding MIPS assembly code? Assume that the variables i, and j are assigned to registers $s0, $s1, respectively. Assume that the base address of the arrays A and B are in registers $s2 and $s3, respectively. B[i] = A[i] - 10