If you hold a spoon in front of your face so that you see your image in the bowl of the spoon, your image is upright when you hold the spoon close to your face, but inverted when you hold the spoon far away. |
Part A Construct the correct explanation why this change occurs. Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
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When you look at spoon you seems to see yourself in a mirror . When you move closer to the spoon .. spoon acts as a concave mirror and you as an object placed inside the focus of mirror then the light rays seems to be diverged and virtual image will be formed which will be upright.
But when you are far away and see your image you are out of focus and image will be inverted as light rays diverge
If you hold a spoon in front of your face so that you see your image...
You hold a metal spoon about 25 cm from your face and look at your own reflection off the back of the spoon. The surface you view is convex with focal length 5 cm. Is the image you see real or virtual? Is the image you see inverted or upright?
A diverging lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = -14.1 cm. The image of the tip of the arrow is located at y = y2 = 6.3 cm. The magnitude of the focal length of the diverging lens is 28.8 cm. light image х 1 Ay 3) A converging lens of focal length fconverging = 9.02 cm is now inserted at x = x3 = -14.36...
you are 20cm from a spherical mirror and see an image of your face that is inverted and the same size as your face. what is the focal length of the mirror.
An object of height 3.6 cm is placed at 24 cm in front of a diverging lens of focal length, f = -18 cm. Behind the diverging lens, there is a converging lens of focal length, f = 18 cm. The distance between the lenses is 5 cm. In the next few steps, you will find the location and size of the final image. Where is the intermediate image formed by the first diverging lens? Image distance from first lens...
An object of height 3.6 cm is placed at 24 cm in front of a diverging lens of focal length, f = -18 cm. Behind the diverging lens, there is a converging lens of focal length, f = 18 cm. The distance between the lenses is 5 cm. In the next few steps, you will find the location and size of the final image. Where is the intermediate image formed by the first diverging lens? Image distance from first lens...
0 An objem wynth the loetion f tmc m is placed 1.6 m in front of a convex mirror with a focal length of -0.75 a. Determine the location of the image. b. Determine the size of the image c. Is the image upright or inverted? length, f J IlIrror is 2 cm from a tooth. The image is located 6cm behind the mirror and is enlarged. a. What kind of mirror is being used? b. What is the focal...
please explain how you are able to tell which statements are true based on the image. PLTUU 1947 The mirror shown in this photo is a concave mirror. Use this photo to answer the following questions. A. Which of the following are true? Choose all that apply. It's a real image. It's a virtual image The image is inverted. The image is upright. The mirror is converging. The mirror is diverging B. Which of the following are true? Choose all...
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
You hold a spherical salad bowl 95cm in front of your face with the bottom of the bowl facing you. The salad bowl is made of polished metal with a 35?cm radius of curvature. A) Where is the image of your 2.0?cm?tall nose located? cm behind the ball B) What is the image's size? cm C)What is the orientation? erect ? inverted ? D) What is the nature (real or virtual)?
You are standing in front of a Jens that projects an image of you onto a wall 1.80 m on the other side of the lens. This image is three times your height: (a) How far are you from the lens? (b) Is your image erect or inverted? (c) What is the focal length of the lens? Is the lens converging or diverging? d) Draw a principal- ray diagram