Calculate the Net Potential Energy of a Na+Cl- ion pair, which is formed by formed by ionic bonding if it is known that the ionic radius of the Na+ ion is 0.095 nm and that of the Cl- ion is 0.181 nm. The value of the electron charge is 1.60 x 10-19 C and of the permittivity of a vacuum is 8.85 x 10-12 C2/(N-m2). Assume n = 9 for NaCl.
Calculate the Net Potential Energy of a Na+Cl- ion pair, which is formed by formed by...
Given 1mol of Na+ and 1 mol of Cl, calculate the energy released when the Na and Cl ions condense as For noninteracting ion pairs;i.e, consider only pairwise interactions Ebond= (z1*z2*e2)/(4*3.14*e0*r0) z1= 1 z2= -1 e0=8.85*10-12 which is the permittivity of a vacuum r0= 283 pm or 283*10-12m which is the distance between ions Ebond= (1*-1*e2)/4*3.14*8.85*10-12*283*10-12)=-490KJ/mol (a) Noninteracting ion squares; i.e., every four ions, 2Na and 2C1 interact with each other, but not with others. Answer: -633kJ/mol (b)1/8 unit cell...
For an Na+Cl- ion pair, attractive and repulsive energies EA and ER, respectively, depend on the distance between the ions (r), according to EA = - 1.436/r ER = 7.32 * (10^-6 / r^8) For these expressions, energies are expressed in electron volts (eV) / Na+Cl- ion pair, and r is the distance in nanometers (nm). The net energy, EN, is the sum of the EA and ER. a) Using graphical software (e.g. Matlab or Excel), create a single plot...
10. For a Na +Cl-ion pair, attractive and repulsive energies Ea and ER, respectively depend on the distance between the ions r, according to 7.32 × 10-6 EA 1.436 For these expressions, energies are expressed in electron volts per Na+ Cl- pair, and ance in nanometers. The net energy Ev is just the sum of the preceding two expressions. (a) Superimpose on a single plot EN,FR, and EA versus r up to 1.0 nm. (b) On the basis of this...
For an Na^+ --Cl^- ion pair, attractive and repulsive energies E_A and E_R, respectively depend on the distance between the ions r, according to E_A = - 1.436/r E_R = 7.32 times 10^-6/r^6 For these expression, energies are expressed in electron volts per Na^+ --Cl^- pair, and r is the distance in nanometers (nm). The net energy E_N is just the sum of the two expressions above. Determine the equilibrium spacing r_0 between the Na^+ and Cl^- Ions. 0) 0.68...
Consider a hypothetical X+-Y' ion pair for which the equilibrium interionic spacing and bonding energy values are 0.35 nm and -6.13 eV, respectively. If it is known that n in E_nhas a value of 10, using r_0 = (a/nb)and E_o = determine explicit expressions for attractive and repulsive energies E_a and E_r of and The answers to Problem 2.18 were expressions for the equilibrium separation r_0 and the bonding energy, which are as follows: If n has a value of...
The total potential energy describing the NaCl lattice is given by: Utot = [ ( -(αe^2) / (4πε 0r) ) + ( A / r^8 ) ], where a is the Madelung constant (a=1.75 for NaCl) and A is a positive constant. 1. What is the physical meaning of the two terms of Utot? Let r0 be the value of the ionic separation r for which Utot is minimum. 2. Deduce an expression of A as a function of r0....
1. a) Caleulate the potential energy of interaction (sometimes called, electrical work) Gin Ad.imel) required to bring two protons from an infinite distance of separation to 0.1 nm; (given that 1A 1010m, permittivity of a vacuum, Co is 8.854187x 10 N 'm2(8.854187 x 1012 Kg'ms A2), Avogadro's number, N 6.022 x 102, elementary charge, 1.602 x 101°C, 1C A s). b) Compare the result from problem 1a) to the electrical work involved when an electron is brought to 0.5nm of...
3) The size of the ionic atmosphere, called the Debye radius, is 1/6, where K is given by where e is the electronic charge, N. is Avogadro's number, s, is the permittivity of vacuum (8.85 x 10- C'N'm ?), e is the dielectric strength of the solvent, kg is the Boltzmann constant, T' is the absolute temperature, and / is the ionic strength (see eq 7.25). Calculate the Debye radius in a 0.010 m aqueous Na SO, solution at 25°C.
For a K+–Cl– ion pair, attractive and repulsive energies EA and ER, respectively, depend on the distance between the ions r, according to EA = − 1.436 r ER = 5.8 × 10−6 r 9 For these expressions, energies are expressed in electron volts (eV) per K+–Cl– pair, and r is the distance in nanometers (nm). The net energy EN is just the sum of the two expressions above (EN = EA + ER). (a) Superimpose on a single plot...
2. a) Calculate the potential energy of interaction (sometimes called, electrical work) (in kl/imol required to bring two sodium ions from an infinite distance of separation to 0.75 nm. (1 A 10-lom, permitivity of a vacuum, eo is 8.854187 x 10-12 C2Nm2 (-8.854187 x 10-12 Kg m3 s A2), Avogadro's number, N 6.022 x 1023, elementary charge, e 1.602 x 101°C, IC A s). b) Compare the result from problem 2a) to the electrical work when a chloride ion is...