Physics Q. A merry-go-round comprises a wooded disk of radius R=2 meters and rotational inertia 148kg·m2...
Physics
Q. A merry-go-round comprises a wooded disk of radius R=2 meters and rotational inertia 148kg·m2 . It rotates with an angular velocity of 2.5rad/s, with a small (point-like!) child of mass 10kg at its center. The child then crawls to the outside rim. What is the the angular velocity now?____rad/s
please explain how to solve for this.
Homework Answers
Here,
let the angular velocity is wf
as there is no torque acting on the axis
Using conservation of angular momentum
initial angular momentum = final angular momentum
148 * 2.5 = (148 + 10 * 2^2)* wf
solving for wf
wf = 1.97 rad/s
the angular velocity is 1.97 rad/s
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