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0.2650 g of a compound of unknown molecular mass were dissolved in 18.00 mL of a...

0.2650 g of a compound of unknown molecular mass were dissolved in 18.00 mL of a non-ionizing solvent with specific gravity of 0.7480. The pure solvent was determined to have a freezing point of 6.80°C. The freezing point of the solution was determined graphically. Trial one yielded a freezing point of 5.31°C for the solution. Trial two indicated the freezing point to be 5.23°C. Kf (solvent) = 12.8 C°/m

a. Calculate the molecular mass of the unknown.

b. If 5.50 grams of solvent freeze out of the original solution, what is the freezing point of the new solution expected to be?

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