Question

(c++)

Using reference variables, calculate the min, max, and average values of a vector of doubles in a function called MinMax. This function will not return any data through the return type. Instead, all values must be returned via reference parameters. Make sure that you pass the parameters in the correct order: vector, min, max, and average.

Answer 1

#include <iostream>
#include <vector>

using namespace std;

void MinMax(vector<double> v, double &min, double &max, double &average) {
    min = v[0];
    max = v[0];
    average = 0;
    for (int i = 0; i < v.size(); ++i) {
        if (v[i] > max) max = v[i];
        if (v[i] < min) min = v[i];
        average += v[i];
    }
    average /= v.size();
}

int main() {
    int size;
    double n, min, max, average;
    cout << "Enter size of the vector: ";
    cin >> size;
    vector<double> v;
    cout << "Enter " << size << " numbers: ";
    for (int i = 0; i < size; ++i) {
        cin >> n;
        v.push_back(n);
    }
    MinMax(v, min, max, average);
    cout << "Min: " << min << endl;
    cout << "Max: " << max << endl;
    cout << "Average: " << average << endl;
    return 0;
}