Name the parts of a confidence interval: x± z σ n x± t s n p±...
Name the parts of a confidence interval:
x± z σ n
x± t s n
p± z p ( 1 − p ) n
Group of answer choices
xbar
[ Choose ] margin of error standard error point estimate
z * sigma/sqrt(n)
[ Choose ] margin of error standard error point estimate
sigma/sqrt(n)
[ Choose ] margin of error standard error point estimate
s/sqrt(n)
[ Choose ] margin of error standard error point estimate
t * s/sqrt(n)
[ Choose ] margin of error standard error point estimate
z*sqrt(pbar(1-pbar)/n)
[ Choose ] margin of error standard error point estimate
pbar
[ Choose ] margin of error standard error point estimate
sqrt(pbar(1-pbar)/n)
[ Choose ] margin of error standard error point estimate
Homework Answers
X bar = point estimate.
z * sigma/sqrt(n) = margin of error
Sigma/sqrt(n) = standard error
s/sqrt(n) = standard error
t*sigma/sqrt(n) = margin of error
z*sqrt(pbar(1-pbar)/n) = margin of error
pbar = point estimate
sqrt(pbar(1-pbar)/n) = standard error
x =30 n=2323, σ=66, confidence =90% a. Use the one-mean z-interval procedure to find a confidence...
x =30 n=2323, σ=66, confidence =90% a. Use the one-mean z-interval procedure to find a confidence interval for the mean of the population from which the sample was drawn. The confidence interval is from to b. Obtain the margin of error by taking half the length of the confidence interval. What is the length of the confidence interval? c. Obtain the margin of error by using the formula E=z(a/2) x o/ square root of n Identify the critical value. What...
ILL UPVOTE 100%!!!!!! Potato Bruises A sample of 150 potatos were spot checked for bruises. "Yes"...
ILL UPVOTE 100%!!!!!!
Potato Bruises
A sample of 150 potatos were spot checked for
bruises. "Yes" indicates that there were visible bruises.
Yes
To determine the total number of "Yes" answers, use
=countif(select data in column A, "Yes")
Yes
To determine the total number of "No" answers, use
=countif(select data in column A, "No")
Yes
Yes
x--the number of bruised potatos
Yes
n--sample size (total number of potatos checked)
Yes
point estimate (pbar)--x/n
Yes
z--use = - norm.s.inv((1-confidence level)/2)
Yes...
Use the normal distribution to find a confidence interval for a proportion p given the relevant...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p^=0.41 and n=475. Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places...
Use the normal distribution to find a confidence interval for a proportion p given the relevant...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for p given that p^=0.39 and n=525. Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places....
Use the normal distribution to find a confidence interval for a proportion p given the relevant...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p = 0.7 and n = 100. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to...
Use the normal distribution to find a confidence interval for a proportion p given the relevant...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p^=0.33 and n=475 . Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal...
Use the normal distribution to find a confidence interval for a proportion p given the relevant...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p^=0.75 and n=140. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Point...
Construct the confidence interval for the population mean μ c: 0.95, x-16.8, σ: 9.0, and n-100...
Construct the confidence interval for the population mean μ c: 0.95, x-16.8, σ: 9.0, and n-100 A 95% confidence interval for μ is OD (Round to one decimal place as needed.) 6.1.27 Use the confidence interval to find the margin of error and the sample mean (1.58,2.06) The margin of error is (Round to two decimal places as needed) 6.1.31 Find the minimum sample size n needed to estimate μ for the given values of c, o, and E. cz...
Use the t-distribution to find a confidence interval for a mean given the relevant sample results....
Use the t-distribution to find a confidence interval for a mean given the relevant sample results. Give the best point estimate for the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed A 90% confidence interval for using the sample results T = 2.9.5 = 0.3, and n = 100 Round your answer for the point estimate to one decimal place, and your answers for the...
Use the t-distribution to find a confidence interval for a mean μ given the relevant sample...
Use the t-distribution to find a confidence interval for a mean μ given the relevant sample results. Give the best point estimate for μ, the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed. A 99% confidence interval for μ using the sample results x¯=93.5, s=34.3, and n=15 Round your answer for the point estimate to one decimal place, and your answers for the margin of...
ILL UPVOTE 100%!!!!!!
Potato Bruises
A sample of 150 potatos were spot checked for
bruises. "Yes" indicates that there were visible bruises.
Yes
To determine the total number of "Yes" answers, use
=countif(select data in column A, "Yes")
Yes
To determine the total number of "No" answers, use
=countif(select data in column A, "No")
Yes
Yes
x--the number of bruised potatos
Yes
n--sample size (total number of potatos checked)
Yes
point estimate (pbar)--x/n
Yes
z--use = - norm.s.inv((1-confidence level)/2)
Yes...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p = 0.7 and n = 100. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to...
Construct the confidence interval for the population mean μ c: 0.95, x-16.8, σ: 9.0, and n-100 A 95% confidence interval for μ is OD (Round to one decimal place as needed.) 6.1.27 Use the confidence interval to find the margin of error and the sample mean (1.58,2.06) The margin of error is (Round to two decimal places as needed) 6.1.31 Find the minimum sample size n needed to estimate μ for the given values of c, o, and E. cz...
Use the t-distribution to find a confidence interval for a mean given the relevant sample results. Give the best point estimate for the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed A 90% confidence interval for using the sample results T = 2.9.5 = 0.3, and n = 100 Round your answer for the point estimate to one decimal place, and your answers for the...
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