A highway safety study found that in 84% of all accidents, the driver was wearing a...
A highway safety study found that in 84% of all accidents, the driver was wearing a seatbelt. Accident reports indicate that 90% of those drivers escaped from serious injury (hospitalized or death) but only 60% of the non-belted drivers were so lucky.
What is the probability that a seriously injured driver was not wearing a seatbelt.
Homework Answers
| P(seriosly injured)=P(not wearing)*P(seriosly injured|not wearing)+P(wearing)*P(seriosly injured|wearing) | |||||||
| =(1-0.84)*(1-0.4)+0.84*(1-0.1)=0.148 | |||||||
| therefore P(not wearing|seriosly injured)=P(not wearing)*P(seriosly injured|not wearing)/P(seriosly injured)=(1-0.84)*(1-0.6)/0.148 =0.4324 | |||||||
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