A positive test charge of 5.0 nC is placed in a uniform electric field of 20,000...

Question

Question

A positive test charge of 5.0 nC is placed in a uniform electric field of 20,000 N / C. The electric force acting on the charge due to this field is:

a. 1.0 x 10 ^ -5N

b. 1.5 x10^ -5N

c. 0.1N

d. 100x10 ^ -6N

Answer 1

Answer #1

F = Q x E

F = (5 x 10^-9 C) x (20000 N/C )

F = 10^-4 N = 100 x 10^-6 N

(d) Answer

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Answer 2

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