A body excutes simple harmonic motion with amplitude 100 mm along the line XY centered on...
A body excutes simple harmonic motion with amplitude 100 mm along the line XY centered on O. When passing through O the body has 50 J of kinetic energy. When it is at a point 40 mm from O, what is the value of its kinetic and potential energies?
Homework Answers
A= amplitude , maximum displacement from mean position
Total energy = kinetic+potential
At mean position potential energy= 0
So, total energy= kinetic energy at the centre O
Total energy= potential energy+ kinetic energy
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