4 KO2(s) + 2 CO2(g) -------> 2 K2CO3(s) + 3 O2(g) How many grams of KO2 are needed to produce 824.0 L of O2 at 13.0 °C and 1.00 atm?
4 KO2(s) + 2 CO2(g) -------> 2 K2CO3(s) + 3 O2(g) How many grams of KO2...
1. 2 KO2(S) + CO2(g) K2CO3(S) + 3/2 O2(g) K = 0.0198 at 315 K AH = -183.6 kJ a. Calculate the value of K at 315 K, for reaction 2: 2. 2 K2CO3(s) + 3 O2(g) 4 KO2(s) + 2 CO2(g) b. Write the K equilibrium expression for reaction 1. c. Calculate the value of Kp for reaction 1 at 315 K.
The reaction between potassium superoxide, KO2, and CO2, 4KO2+2CO2→2K2CO3+3O2 is used as a source of O2 and absorber of CO2 in self-contained breathing equipment used by rescue workers. a). How many moles of O2 are produced when 0.475 mol of KO2 reacts in this fashion? b). How many grams of KO2 are needed to form 8.0 g of O2? c). How many grams of CO2 are used when 8.0 g of O2 are produced?
24-11 pm 6.86. Rescue Breathin breathing devices, like + 6.96. Breathing Devices Self-contained self-rescue devices, like the one shown in Figure P6.86, +CO, into O2 according to the following reaction: 4 KO2() + 2 CO2(g) → 2 K2CO3(-) + 3 O2(g) any grams of KO2 are needed to produce 100.0 L of 0, at 20°C and 1.00 atm? Dalt Conce 6.97 6.99 6.99 6.10 6. FIGURE P6.86
potassium superoxide. KO2 reacts with carbon dioxide, CO2 according to the following equations: 4 KO2 + 2 CO2 --> 2 K2CO3 + 3 O2 When 8 moles of KO2 and 3 moles of CO2 react, the limiting reagent and moles of O2 produced is: KO2 limiting, 6.0 moles O2 CO2 limiting, 12.0 moles O2 KO2 limiting, 3.0 moles O2 CO2 limiting, 4.5 moles O2
1. For the balanced chemical reaction: 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(ℓ), how many moles of H2O are produced when 0.669 mol of NH3 react? 2.For the balanced chemical reaction: 4 KO2(s) + 2 CO2(g) → 2 K2CO3(s) + 3 O2(g) determine the number of moles of each of the products that are formed when 6.88 mol of KO2 react. Please explain, thanks!
4 Na(s) + O2(g) → Na2O(s) a. How many grams of sodium are needed to completely react with 2.80 liters of Oz at STP? b. What volume of O, at 25°C and 2.00 atm is needed to completely react with 4.60 grams of sodium?
A mixture containing KClO3, K2CO3, KHCO3, and KCl was heated, producing CO2,O2, and H2O gases according to the following equations: 2KClO3(s)2KHCO3(s)K2CO3(s)→→→2KCl(s)+3O2(g)K2O(s)+H2O(g)+2CO2(g)K2O(s)+CO2(g) The KCl does not react under the conditions of the reaction. 100.0 g of the mixture produces 1.70 g of H2O, 12.66 g of CO2, and 4.00 g of O2. (Assume complete decomposition of the mixture.) You may want to reference (Page) Section 3.7 while completing this problem. a. How many grams of KClO3 were in the original mixture?...
Given the following: 4 KO2 + 2 H2O ===> 4 KOH + 3 O2 Find the grams KO2 and H2O needed to make 1350 grams O2
Question 2 Consider the following reaction: 4 KO2(s) + 2 H2O(1) ® 4 KOH(s) + 3 O2(g) Suppose 83 grams of KO2 are added to 27 grams of H20. What is the limiting reactant and how many grams of KOH is produced (theoretically)? Answer below and show your work on the work sheet. Label your work as #2. HTML
2KHCO3(s) K2CO3(s) + CO2(g) + H2O(l) How many moles of CO2 will be produced if 315g of potassium hydrogen carbonate are heated? ‘’a. 1.58 mol b. 15.8 mol c.3.15 mol d. 0.315 mol e. 158 mol