Alice uses the RSA public key modulus n = pq = 23761939. Through espionage, Eve discovers that (p − 1)(q − 1) = 23752000. Determine p, q. Show your work
i got perfect values
Please thumsup for my effort
Thank you and all the best
Alice uses the RSA public key modulus n = pq = 23761939. Through espionage, Eve discovers...
Using RSA Implementation: 1. Alice's RSA public key is given by (e, n) = (59, 1189). = (a) Determine Alice's private key (d, n). (b) Bob sends his first message Mi 67 to Alice, encrypting it with RSA using Alice's public key. He obtains a cypher text Cị that gets forwarded to Alice. What is Cį? (c) Bob sends his second message M2 to Alice, encrypting it with RSA using Alice's public key. Eve, who was eavesdropping on the commu-...
(8) In an RSA cryptosystem, Bob’s public key is (n = 629, e = 43). Alice uses this public key to encrypt the word “MARCH” and send the ciphertext to Bob. First, she represents this word in ASCII where the capital letters A, B, C, . . . , X, Y, Z are represented by integers 65, 66, 67, . . . , 88, 89, 90 respectively. Then she encrypts the five integers that represent M, A, R, C, H...
7.2.10 Alice and Bob have RSA setupe with the same modulus n 15251, with eneryption keys ex - i and ea 503, and Alice has (secret) decryption key d 4091. Alice wants to break into Bob's stuff. Without knowing the prime factorization of 15251, how does she easily ind Bob's encryption exponent, or something Js (This is a common modulus attack.) 7.2.10 Alice and Bob have RSA setupe with the same modulus n 15251, with eneryption keys ex - i...
Exercise 1 (2 pts). Alice has her RSA public key (n,e) where n = 247 = 13·19 and e = 25. What is her secret key and what is her signature corresponding to the message M = 63? n=247=13 x 19
Problem 3 In RSA, we will consider what happens when Alice makes the mistake of choosing p,q too close together. Her method is as follows. She chooses p a random large prime, and then chooses q to be the smallest prime greater than p . You are Eve, and Alice's public key is (e,n) where e=13 and n is 4149515568880992958512407863691161151012446232242436899995657329690652811412991293413200434314186514261288537546721977134041420919065144782418033157091025480140853599374890776565691 (Make sure to copy all of n, which has 181 digits). Find Alice's private key d using python
5. Alice wishes to send the message m4 to Bob using RSA encryption. She looks up Bob's public key and finds that it is (n-55. c= 3 (a) Specify exactly what information Alice sends to Bob (b) What is Bob's private key? Show how he would use it to recover Alice's message (c) Explain why Bob should never use this choice of public key in real life. 5. Alice wishes to send the message m4 to Bob using RSA encryption....
Exercise 1 (2 pts). In an RSA cryptosystem, Bob's public key is (n = 253, e = 3), Alice uses this public key to encrypt a message M for Bob. The resulting ciphertext is 110. Recover the message M. (You can use online modular calculators available at the Web.)
6. An RSA cryptosystem has modulus n-299, which is a product of the primes 23 and 13. Your public encoding key e-59. What is your secret decoding key d? (a) 179 (b) 205 (c 214 (d) none of these. 6. An RSA cryptosystem has modulus n-299, which is a product of the primes 23 and 13. Your public encoding key e-59. What is your secret decoding key d? (a) 179 (b) 205 (c 214 (d) none of these.
p=3, q=7 Suppose that Bob wants to create an example of an RSA public-key cryptosystem by using the two primes p ??? and q ???. He chooses public encryption key e He was further supposed to compute the private decryption key d such that ed 1 mod A(pq)). However, he confuses A and and computes instead d' such that ed' =1 (mod P(pq)). (i) Prove that d' works as a decryption key, even though it is not necessarily the same...
SOLVE cybersecurity Alice creates an RSA key by selecting primes p=5 and q=11. This results in n=55. Alice selects e=21 and wants to encrypt the value 3. The result will be: