Suppose an element from group IIIA(13), and period 3 of the periodic table forms an ionic compound with the element that has an electronic configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 . What would be the formula of the compound, and what would be the name of the compound?
Ans :
The group IIIA element of period 3 is Aluminium (Al).
The element with the electronic configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 is : Bromine (Br)
In the ionic compound formed between these two Al will be cation and Br will be anion , so the formula of the compound will be :
AlBr3 , and the name of the compound will be : Aluminium bromide.
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