Show that
q → (p ∧ q) ∨ (¬p ∧¬q) →p |
is a tautology using De-Morgan Laws
(( with showing the steps ))
In (Discrete Structures course)
Show that q → (p ∧ q) ∨ (¬p ∧¬q) →p is a tautology using De-Morgan...
Prove that (¬q ∨ (¬p → q)) →p is a tautology using propositional equivalence and the laws of logic. Step Number Formula Reason
How can I prove (p ∧ q) → (p ∨ q) is a tautology.
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