Practice Question
The widths of platinum samples manufactured at a factory have a
mean of 1 cm and a standard deviation of 0.4 cm. Find the z-scores
that correspond to each of the following widths. Round your answers
to three decimal places, if necessary.
1) 1.5 cm
z= _____
2) 0.7 cm
z=______
Solution :
Given that mean μ = 1 and a standard deviation σ = 0.4
1) X = 1.5
=> Z = (X - μ)/σ
= (1.5 - 1)/0.4
= 1.25
=> If X = 1.5 then the Z-score is 1.250
2) X = 0.7
=> Z = (X - μ)/σ
= (0.7 - 1)/0.4
= -0.75
=> If X = 0.7 then the Z-score is -0.750
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