After absorbing 1.75 kJ of heat, a 0.454 kg block of nickel has a temperature of 36.3°C. What was its temperature before heating? (The specific heat of nickel is 0.440 J/gK
Give answer in Celsius
Given:
Q = 1.75 KJ = 1750 J
m = 0.454 Kg = 454 g
C = 0.44 J/g.oC
Tf = 36.3 oC
use:
Q = m*C*(Tf-Ti)
1750.0 = 454.0*0.44*(36.3-Ti)
36.3 - Ti = 8.8 oC
Ti = 27.5 oC
Answer: 27.5 oC
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