The reaction X2(g)<->2X(g) occurs in a closed
reaction vessel at constant volume and temperature. Initially, the
vessel contains only X2 at a pressure of 1.75 atm. After the
reaction reaches equilibrium, the total pressure is 2.65atm.
what is the value of the equilibrium constant, Kp, for the
reaction?
X2(g) <-> 2X(g)
1.75
0 (initial)
1.75-x 2x
(equilibrium)
Total pressure at equilibrium = 1.75-x+2x
2.65 = 1.75+x
x = 0.90 atm
Now use:
Kp = p(X)^2 / p(X2)
= (2x)^2 / (1.75-x)
= (2*0.90)^2 / (1.75 - 0.90)
= 3.24 / 0.85
= 3.81
Answer: 3.81
The reaction X2(g)<->2X(g) occurs in a closed reaction vessel at constant volume and temperature. Initially, the...
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