The equilibrium constant Kp of the reaction below is 7.69 at 830°C. 2S0,(g) 2S0,(g) +0,(g) 1st...

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Answer 1

Answer #1

2SO3(g) ---------------> 2SO2(g) + O2(g)

I 0.1 0 0

C -2x 2x x

E 0.1-2x 2x x

Kp = P^2SO2*PO2/P^2SO3

7.69 = (2x)^2*x/(0.1-2x)^2

7.69*(0.1-2x)^2 = 4x^3

x = 0.0464

PSO3 = 0.1-2x = 0.1-2*0.0464 =0.0072atm

PO2 = x = 0.0464atm

PSO2 = 2x = 2*0.0464 = 0.0928atm

Answer 2

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