Given a number, calculate how many years into the future it is,
and what date. Assume no leap years.
For example:
Please enter a day of the year (0 to exit): 1
jan 1
Please enter a day of the year (0 to exit): 365
dec 31
Please enter a day of the year (0 to exit): 366
1 year
jan 1
Please enter a day of the year (0 to exit): 0
Thanks for playing!
My current code:
#include <iostream>
#include <string>
using namespace std;
int main() {
const int MonthDays[]={31, 59, 90, 120, 151,
181, 212, 243, 273, 304, 334, 366};
const string MonthName[] = {"jan", "feb", "mar",
"apr", "may", "jun", "jul", "aug", "nov", "dec"};
int day, year, index;
while(1){
cout<<"Please enter a day of the year (0
to exit): ";
cin>>day;
cout<<day;
cout<<endl;
if(day==0){
break;
}
while(day>0){
if(day>365){
year=day/366;
day=day%365;
cout<<year<<" Year"<<endl;
}
day=day%365;
if(day==0){
cout<<"dec 31"<<endl;
}
if(day>=1&&day<=31){
cout<<MonthName[index]<<" "<<day;
cout<<endl;
}
else {
cout<<MonthName[index]<<"
"<<day-MonthDays[index-1];
cout<<endl;
}
cout<<"Please
enter a day of the year (0 to exit): ";
cin>>day;
cout<<day<<endl;
}
}
cout<<"Thanks for playing!";
return 0;
}
----------------------------------------
my error message:
==================== YOUR OUTPUT =====================
0001: Please~enter~a~day~of~the~year~(0~to~exit):~1
0002: jan~1
0003: Please~enter~a~day~of~the~year~(0~to~exit):~365
0004: dec~31
0005: jan~0
=================== MISMATCH FOUND ON LINE 0005: ===================
ACTUAL : jan~0
EXPECTED: Please~enter~a~day~of~the~year~(0~to~exit):~31
======================================================
Adjust your program and re-run to test.
#include <iostream> #include <string> using namespace std; int main() { const int MonthDays[]={31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; const string MonthName[] = {"jan", "feb", "mar", "apr", "may", "jun", "jul", "aug", "sep", "oct", "nov", "dec"}; int day, year=0, index; while(1){ cin>>day; cout<<endl; if(day==0){ break; } index = 0; year = 0; while(day > 365) { day = day - 365; year++; } if(year != 0) { cout<<year<<" Year"<<endl; } index = 0; while(day > MonthDays[index]) { day = day - MonthDays[index]; index++; } cout << MonthName[index] << " " << day << endl; } cout<<"Thanks for playing!"; return 0; }
your code did not even have the names of all months.. I have corrected everything and as you can see in screenshot it works well. Please upvote. Thanks!
Given a number, calculate how many years into the future it is, and what date. Assume...
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main.cpp
#include <iostream>
#include <vector>
#include <string>
#include "functions.h"
int main()
{
char option;
vector<movie> movies;
while (true)
{
printMenu();
cin >>
option;
cin.ignore();
switch (option)
{
case 'A':
{
string nm;
int year;
string genre;
cout << "Movie Name: ";
getline(cin, nm);
cout << "Year: ";
cin >> year;
cout << "Genre: ";
cin >> genre;
//call you addMovie() here
addMovie(nm, year, genre, &movies);
cout << "Added " << nm << " to the catalog"
<< endl;
break;
}
case 'R':
{
string mn;
cout << "Movie Name:";
getline(cin, mn);
bool found;
//call you removeMovie() here
found = removeMovie(mn, &movies);
if (found == false)
cout << "Cannot find " << mn << endl;
else
cout << "Removed " << mn << " from catalog"
<< endl;
break;
}
case 'O':
{
string mn;
cout << "Movie Name: ";
getline(cin, mn);
cout << endl;
//call you movieInfo function here
movieInfo(mn, movies);
break;
}
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{
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printCatalog(movies);
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}
case 'F':
{
string inputFile;
bool isOpen;
cin >> inputFile;
cout << "Reading catalog info from " << inputFile
<< endl;
//call you readFromFile() in here
isOpen = readFile(inputFile, &movies);
if (isOpen == false)
cout << "File not found" << endl;...
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