Run at 25.00 °C, the rate constant was found to be 2.300 X 10^-5 1/M sec....
Run at 25.00 °C, the rate constant was found to be 2.300 X 10^-5 1/M sec. Run at 30.00 °C, the rate constant was found to be 3.621 X 10^-5 1/M sec. Calculate the activation energy (Use R=8.315 J/K mol), with units of KJ/mole, and report the answer to 3 significant figures.
Homework Answers
Using Arrehious equation
ln(K2/K1) =( Ea/R)×(1/T1 - 1/T2)
ln(3.621×10-5/2.30×10-5) = (E/8.314)(1/298-1/303)
E = 68.1 kJ/mol
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Run at 25.00 °C, the rate constant was found to be 2.300 X 10^-5
1/M sec....
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