Assume there is a string s. Print out “Not found” if s does not contain the...
Assume there is a string s. Print out “Not found” if s does not contain the letter ‘x’ otherwise print the index. c++
Homework Answers
// Assuming s is already declared and initialized a value
bool foundX = false; // set found to false
for (int i = 0; i < s.size(); ++i) { // go through all characters of String s
if (s[i] == 'x') // if character is 'x'
foundX = true; // then set found to true
}
if (foundX) // if x is found
cout << "Not found"; // then print Not found
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