You push a box weighing 6.72 kg along a horizontal floor with a force 16.6 N...
You push a box weighing 6.72 kg along a horizontal floor with a force 16.6 N at an angle 38.3⁰ below the horizontal. The coefficient of friction between the box and the floor is 0.116. (a) What is the frictional force on the block? (b) What is the acceleration of the block?
Homework Answers
Normal force acting on the block
N = mg + F sin x
N = 6.72* 9.8 + 16.6* sin 38.3
N = 76.14 N
a)
Frictional force on block
f = uN = 0.116 x 76.14 = 8.83 N
=======
b)
ma = F Cos x - f
6.72 x a = 16.6 cos38.3 - 8.83
Acceleration, a = 0.62 m/s^2
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