Question

I push a 16.5-kg box across a floor, which has a kinetic frictional force of Ff = 27.5 N. If my push of FA = 32 N gives it an acceleration of 0.35 m/s2, what is the coefficient of kinetic friction?

Answer 1

Given data-

Ff = 27.5 N

Fa = 32 N , m = 16.5kg , a=0.35 m/s²

Ff = 27.5 N

$\mu _{k}$ (N) = 27.5

$\mu _{k}$ (Mg) = 27.5

$\mu _{k}$ (16.5*10) = 27.5

$\mu _{k}$ = 0.167

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