A 615-kg elevator starts from rest and moves upward for 2.90 s with constant acceleration until it reaches its cruising speed, 1.76 m/s. (a) What is the average power of the elevator motor during this period? Incorrect: Your answer is incorrect. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. hp (b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with constant speed.) hp
A 615-kg elevator starts from rest and moves upward for 2.90 s with constant acceleration until...
A 612-kg elevator starts from rest and moves upward for 4.50 s with constant acceleration until it reaches its cruising speed, 1.64 m/s. (a) What is the average power of the elevator motor during this period? hp (b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with constant speed.) hp
A 639-kg elevator starts from rest and moves upward for 3.40 s with constant acceleration until it reaches its cruising speed, 1.78 m/s. (a) What is the average power of the elevator motor during this period? (b) How does this amount of power compare with its power during an upright trip with constant speed?
A 500 kg elevator starts from rest. It moves upward for 2.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s. a.) What is the average power of the elevator motor during this period? b.) How does this power compare with the motor power when the elevator moves at its cruising speed?
A 700 kg elevator starts from rest. It moves upward for 5.00 s with constant acceleration until it reaches its cruising speed, 1.75 m/s. (b) How does this power compare with the motor power when the elevator moves at its cruising speed? Pcruising = 12400 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy...
An elevator starts from rest with a constant upward acceleration. It moves 2.0 meters in the first 0.6 seconds. A passenger in the elevator is holding a 3 kg package by a vertical string. What is the tension in the string during the acceleration process? [Hint: remember Newton's 3rd law]
2. The elevator (E) starts from rest and moves upward with a constant acceleration. If the counterweight (W) movesa distance of 32 feet in 4 seconds, determine: A. The acceleration of the elevator, B. The acceleration of point C on the cable, and C. The velocity of the elevator after 4 seconds. E.
008 10.0 points An elevator starts from rest with a constant upward acceleration and moves 1 m in the first 1.8 s. A passenger in the elevator is holding a 4.6 kg bundle at the end of a vertical cord. What is the tension in the cord as the ele- vator accelerates? The acceleration of gravity is 9.8 m/s. Answer in units of N.
When a 2.50-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.38 cm. (a) What is the force constant of the spring? _________N/m? (b) How much work must an external agent do to stretch the same spring 7.60 cm from its unstretched position?_________J? ______________________________________________________________________________________________ A 620-kg elevator starts from rest and moves upward for 3.00 s with constant acceleration until it reaches its cruising speed, 1.63 m/s. (b) How does this amount...
A skier of mass 72 kg is pulled up a slope by a motor-driven cable. (a) How much work is required to pull him 85 m up a 30 degree slope (assumed frictionless) at a constant speed of 2.2 m/s? Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. (b) What power (expressed in hp) must a motor have to perform this task? Your response differs significantly from the correct...
A dentist's drill starts from rest. After 2.90 s of constant angular acceleration it turns at a rate of 2.75 ✕ 104 rev/min. (a) Find the drill's angular acceleration. (b) Determine the angle (in radians) through which the drill rotates during this period. rad