A dentist's drill starts from rest. After 2.90 s of constant angular acceleration it turns at a rate of 2.75 ✕ 104 rev/min. (a) Find the drill's angular acceleration. (b) Determine the angle (in radians) through which the drill rotates during this period. rad
(a)
first convert rev/min to
rad/s
ω = 2.75*104 rev/min = (2.75*104 rev/min)(2π rad/rev)(min / 60 s) = 2879.79 rad/s
α = (ω - ωo)/t
α = 2879.79 rad/s / (2.90 s)
α = 993.03 rad/s^2
(b)
θ = αt^2 / 2
θ = (993.03 rad/s^2)(2.90 s)2 / 2
θ = 4.175*103 rad
A dentist's drill starts from rest. After 2.90 s of constant angular acceleration it turns at...
A dentist's drill starts from rest. After 3.10 s of constant angular acceleration it turns at a rate of 2.80 ✕ 104 rev/min. (a) Find the drill's angular acceleration. _______ rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. ________ rad
A dentist's drill starts from rest. After 3.20 s of constant angular acceleration it turns at a rate of 2.70 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad
A dentist's drill starts from rest. After 2.50 s of constant angular acceleration it turns at a rate of 2.55 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad
A dentist's drill starts from rest. After 4.60 s of constant angular acceleration it turns at a rate of 2.55 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad
1. A dentist's drill starts from rest. After 2.90s of constant angular acceleration, it turns at a rate of 2.55 x 10* rev/min. (a) Find the drill's angular acceleration. (b) Determine the angle through which the drill rotates during this period.
HELP!! 2. (-15 Points] DETAILS A dentist's drill starts from rest. After 3.40 s of constant angular acceleration it turns at a rate of 2.25 x 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad
A dentist's drill starts from rest and undergoes uniform angular acceleration for a period of 0.115 s until it turns at a rate of 2.15 ✕ 104 rev/min. A dentist's drill starts from rest and undergoes uniform angular acceleration for a period of 0.115 s until it turns at a rate of 2.15 x 104 rev/min. (a) What is the drill's angular acceleration (in rad/s2)? (Enter the magnitude.) rad/s2 (b) What is the angle (in radians) through which the drill...
4. A dentist's drl starts from rest. After 3.20 s of constant an- gular acceleration, it turns at a rate of 2.51 × 104 rev/min. (a) Find the drill's angular acceleration. (b) Determine the angle (in radians) through which the drill rotates during this period.
A dentist's drill starts from rest. After 3.30 s of constant angular acceleration, it turns at a rate of 2.53 X 10" rev/min. (a) Find the drill's angular acceleration. 127778 X Your response differs from the correct answer by more than 10%. Double check your calculations. rad/s(along the axis of rotation) (b) Determine the angle through which the drill rotates during this period. 0.8743*10** 4 X Your response differs from the correct answer by more than 10% Double check your...
1)A dentist's drill starts from rest. After 4.00 s of constant angular acceleration it turns at a rate of 2.00 ✕ 104 rev/min. a)Find the drills angular acceleration ____rad/s^2 b) Determine the angle (in radians) through which the drill rotates during this period____rad 2)The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 10.0 s. At this point, the person doing the laundry opens the lid, and a...