Question

A dentist's drill starts from rest. After 3.10 s of constant angular acceleration it turns at...

A dentist's drill starts from rest. After 3.10 s of constant angular acceleration it turns at a rate of 2.80 ✕ 104 rev/min.

(a) Find the drill's angular acceleration.
_______ rad/s2
(b) Determine the angle (in radians) through which the drill rotates during this period.
________ rad

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Answer #1

@ wo wo tat. 2.80x10x20 = 0 +(« *3\0) ra=a46 radar o o= txt = txau6x(3:10)2 5o = 4545 red]

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