1. What is the reduced mass of an H35 Cl molecule? Give your answer in both kg and amu.
Reduced mass = √(m1m2/(m1+m2))
m1 (H) = 1.0078 m2 (35 Cl) = 34.9688
Reduced mass = √(1.0078×34.9688)/(1.0078+34.9688)
= 0.9796 amu
1 amu = 1.661×10-27 kg
Reduced mass = 0.9796×1.661×10-27 Kg
= 1.627×10-27 Kg
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1. What is the reduced mass of an H35 Cl molecule? Give your answer in both...
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