An oscillator has an equation x(t) = (0.45 m) cos ( 359 t)
Assuming ω is in SI units, calculate the frequency in Hz to 2 sf.
x(t) = (0.45 m) cos ( 359 t)
compare it with
x(t) =A*cos(ω*t)
so ω = 359 rad/s
ω = 2*pi*f
f = ω /2pi = 359/(2*pi) =57.1366246 Hz
the frequency = 57 Hz answer
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