The oxygen molecule, O2, has a total mass of
5.30×10-26 kg and a rotational inertia of
1.94×10-46kg-m2 about an axis
perpendicular to the center of the line joining the atoms. Suppose
that such a molecule in a gas has a speed of
1.48×102m/s and that its rotational kinetic
energy is two-thirds (2/3) of its translational kinetic
energy.
Find its angular velocity.
Mass of the oxygen molecule = m = 5.3 x 10-26 kg
Rotational inertia of the oxygen molecule = I = 1.94 x 10-46 kg.m2
Speed of the molecule = V = 1.48 x 102 m/s
Angular velocity of the molecule =
Translational kinetic energy of the molecule = KET = mV2/2
Rotational kinetic energy of the molecule = KER = I2/2
The rotational energy of the molecule is two-thirds of the translation energy of the molecule.
KER = (2/3)KET
= 1.99 x 1012 rad/s
Angular velocity of the molecule = 1.99 x 1012 rad/s
The oxygen molecule, O2, has a total mass of 5.30×10-26 kg and a rotational inertia of...
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