A 1.00g sample of an unknown halide of Cu, CuX2 (X is a halide ion), is dissolved in a 25.0 g of water. The freezing point of the solution is found to be -1.00 C. Assuming 100% dissociation of the halide, what is the identity of halogen X? Use a Kf for water of 1.86 C/m.
A 1.00g sample of an unknown halide of Cu, CuX2 (X is a halide ion), is...
A 10.5 g sample of FeCl3 is dissolved in 1.50 x 10^2 g of water, with complete dissociation of the iron (III) chloride. Calculate the freezing point of the solution. Remember the Kf = 1.86 °C/m for water.
A 15.3 g sample of a compound known to contain 3 ion species is dissolved in 110 g of water. The boiling point of the solution is 103.0 degrees Celsius. What is the molar mass of the compound? Additional Info: Physical Properties of water Freezing point: 0.00 degrees Celsius Boiling point: 100 degrees Celsius Kf: 1.86 Degrees Celsius/m Kb: 0.512 degrees Celsius/m
A 12.5855 g sample of an unknown compound (X) is dissolved in 32.0000 g of water. The resulting solution has a freezing point of – 4.3oC. What is the molar mass of X? Kf = 1.858 oC/m.
A solution containing 1.00 g of an unknown non-electrolyte liquid and 9.00 g water has a freezing point of -3.33 oC. The Kf = 1.86 oC/m for water. Calculate the molar mass of the unknown liquid, in g/mol.
Same Question and data but different parts. Please solve for all three. Last attempt left QUESTION 1 The data given in question-1 is used in the remainder of the postlab assignment questions. A 2.0 g of unknown material was dissolved in 9.00 mL of water (density of water = 1.0 g/mL) The freezing point of pure water is 0.00 °C and Kf of water is 1.86 °C/m. If the solution made above shows a new freezing point at -2.76 °C,...
The normal freezing point of water, H2O is 0.00 °C and its Kfn value is 1.86 °C/m. Assuming complete dissociation of the electrolyte, if 12.39 grams of sodium nitrate (NaNO3, 85.00 g/mol) are dissolved in 245.8 grams of water what is the freezing point of the solution? The normal boiling point of water, H20 is 100.00 °C and its Kbp value is 0.512 °C/m. Assuming complete dissociation of the electrolyte, if 13.39 grams of potassium chloride (KCI, 74.55 g/mol) are...
An unknown sample weighs 0.2436 g was dissolved in 20.0 mL of cyclohexane (density = 0.779 g/mL). The freezing point depression (∆Tf) was 2.5°C. Calculate the molar mass of the unknown substance. (Kf = 20.5 °C/m) ∆Tf = Kf m where Kf is the freezing point depression constant and m is molality. 526 g/mol 1.50 g/mol 128 g/mol 2.44 g/mol
A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene ( C7H8 = 92 g/mol) and the freezing point is lowered by 1.33 oC. What is the molecular weight of the organic compound? (Kf = 5.12 oC/m).
Quinine is a natural product extracted from the bark of the cinchona tree, which is native to South America. Quinine is used as an antimalarial agent. When 1.68 g of quinine is dissolved in 25.0 g of cyclohexane, the freezing point of the solution is lowered by 4.31∘ C. The freezing point and Kf constant for cyclohexane can be found here. Calculate the molar mass of quinine. Solvent Formula Kf valueNormal freezing Kb value Normal boiling point (°C) 0.00 5.49...
What is the freezing point in ∘C of each of the solutions below? For water, Kf = 1.86(∘C ⋅ kg)/mol. A solution of 15.0 g of LiCl in 168.0 g of water at 45.0 ∘C, assuming complete dissociation.