Question

C programming

Game of life GAME !!!!

I need some code for this function :

/*

* get_grid creates new memory for a "grid".

* x is the height and y is the width.

*/

char** get_grid(int x, int y){

}

/*

* print_grid attempts to print an x height

* by y width grid stored at the location

* provided by grid

*/

void print_grid(int x, int y, char** grid){

}

Answer 1

#include <stdio.h>

#include<stdlib.h>

char** get_grid(int x, int y);

void print_grid(int x, int y, char** grid);

/*

* get_grid creates new memory for a "grid".

* x is the height and y is the width.

*/

char** get_grid(int x, int y) {

  

char **ptr;

ptr = (char **)malloc(x * sizeof(char *));

  

for(int i = 0; i < x; i++)

ptr[i] = (char *)malloc(y * sizeof(char *));

  

for (int i = 0; i < x; i++) {

for (int j = 0; j < y; j++) {

if (ptr[i][j] == 0)

printf(".");

else

printf("*");

}

printf("\n");

}

printf("\n");

  

return ptr;

}

/*

* print_grid attempts to print an x height

* by y width grid stored at the location

* provided by grid

*/

void print_grid(int x, int y, char** grid) {

char **future;

future = (char **)malloc(x * sizeof(char *));

  

for(int i = 0; i < x; i++)

future[i] = (char *)malloc(y * sizeof(char *));

  

// Loop through every cell

for (int l = 1; l < x - 1; l++)

{

for (int m = 1; m < y - 1; m++)

{

// finding no Of Neighbours that are alive

int aliveNeighbours = 0;

for (int i = -1; i <= 1; i++)

for (int j = -1; j <= 1; j++)

aliveNeighbours += grid[l + i][m + j];

  

// The cell needs to be subtracted from

// its neighbours as it was counted before

aliveNeighbours -= grid[l][m];

  

// Implementing the Rules of Life

  

// Cell is lonely and dies

if ((grid[l][m] == 1) && (aliveNeighbours < 2))

future[l][m] = 0;

  

// Cell dies due to over population

else if ((grid[l][m] == 1) && (aliveNeighbours > 3))

future[l][m] = 0;

  

// A new cell is born

else if ((grid[l][m] == 0) && (aliveNeighbours == 3))

future[l][m] = 1;

  

// Remains the same

else

future[l][m] = grid[l][m];

  

}

}

for (int i = 0; i < x; i++)

{

for (int j = 0; j < y; j++)

{

if (future[i][j] == 0)

printf(".");

else

printf("*");

}

printf("\n");

}

}

int main(int argc, const char * argv[]) {

print_grid(10,10, get_grid(10,10));

  

return 0;

}