A particle has a charge of -3.05 nC . Part A Find the magnitude of the electric field due to this particle at a point 0.235 m directly above it. Find the direction of the electric field at this point. Find the direction of the electric field at this point. Part C At what distance from the particle does its electric field have a magnitude of 10.5 N/C ?
A particle has a charge of -3.05 nC . Part A Find the magnitude of the...
A particle has a charge of -3.10 nC . A.)Find the magnitude of the electric field due to this particle at a point 0.235 m directly above it. B.) Find the direction of the electric field at this point. (upward or downward) C.) At what distance from the particle does its electric field have a magnitude of 10.5 N/C ?
1. A particle with a charge of +4.20 nC is in a uniform electric field E⃗ directed to the negative x direction. It is released from rest, and after it has moved 6.00 cm , its kinetic energy is found to be 1.50×10−6 J . a. What work was done by the electric force? b. What was the change in electric potential over the distance that the charge moved? c. What is the magnitude of E? d. What was the change...
A -4.00 nC point charge is at the origin, and a second -5.50 nC point charge is on the x-axis at x = 0.800 m PART A Find the electric field (magnitude and direction) at point on the x-axis at x = 0.200 m. PART B Find the electric field (magnitude and direction) at point on the x-axis at x = 1.20 m. PART C Find the electric field (magnitude and direction) at point on the x-axis at x =...
Each of the protons in a particle beam has a kinetic energy of 3.05 Times 10^-15 J. what are the magnitude and direction of the electric field that will stop these protons in a distance of 1.40 m? Magnitude N/C Direction
Consider the charge arrangement in the figure below where ql is directly to the left of location "p, and q2 is directly below location "p". q1 has a positive charge of +12.0 nC, q2 has a negative charge of -14.5 nC, and both charges are a distance of 55.0 mm away from location "p". What is the magnitude of the net electric field at location "p" due to these two charges? 曊; 92 N/C Find the magnitude and direction of...
A straight, nonconducting plastic wire 8.50 cm long carries a charge density of 130 nC/m distributed uniformly along its length. It is lying on a horizontal tabletop. Part a) Find the magnitude and direction of the electric field this wire produces at a point 5.00 cm directly above its midpoint. Part b) Is electric field directed upward or downward Part c) If the wire is now bent into a circle lying flat on the table, find the magnitude and direction...
Constants Part A A point charge q.--4.00 nC is at the point z. 0.60 m, 3-0801 m,and a second point charge q2 = +6.00 nC is at the point. 0.60 m,y0 Calculate the magnitude of the net electric field at the origin due to these two point charges N/C Submit ▼ Part B Calculate the direction of the net electric field at the origin due to these two point charges. 四? counterclockwise from +-axis Submit
Two stationary positive point charges, charge 1 of magnitude 3.05 nC and charge 2 of magnitude 1.50 nC , are separated by a distance of 60.0 cm . An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed vfinal of the electron when it is 10.0 cm from charge 1? (m/s)
A positive charge of magnitude Q1 = 6.5 nC is located at the origin. A negative charge Q2 = -7.5 nC is located on the positive x-axis at x = 14.5 cm from the origin. The point P is located y = 15 cm above charge Q2Part (a) Calculate the x-component of the electric field at point P due to charge Q1. write your answer in units of N/C. Part (b) Calculate the y-component of the electric field at point P...
A+2.00 nC point charge is at the origin, and a second -5.00 nC point charge is on the x-axis at x=0.800 m.Part AFind the electric field (magnitude and direction) at the point on the x-axis where x=0.200 m.Part BFind the electric field (magnitude and direction) at the point on the x-axis where x=1.20 m.Part CFind the electric field (magnitude and direction) at the point on the x-axis where x=-0.200 m.