Question

Define the function choco(n) to solve the following problem:

A company packages and sells boxes with chocolates. The boxes come in two sizes: large and small. The “large” box contains 48 chocolates and the “small” box contains 8 chocolates. The company makes the most gain by selling large boxes: CDN$26 each. Small boxes produce less gain but still some: a small box provides the company CDN$4 gain. On the other hand, the company loses CDN$ 2 per chocolate not used. Thus, the company will attempt to package as many large boxes as possible, and then as many small boxes as possible.

This function receives as input in the parameter variable a number of chocolates available and it should return a string with the following information: first, the number of large boxes to package, followed by two dots ("..") followed by the number of small boxes to package, followed again by two dots, followed by the number of unpackaged chocolates , followed by two dots and finally the money the company makes, considering the gains (because of the boxes packaged) minus the losses (because of the unused chocolates).

For example, calling this function as choco(503) should return '10..2..7..254 ', because with 503 chocolates the company can package

- 10 large boxes,

- 2 small boxes

- and there are 7 unused chocolates.

In this example the company makes CDN$ 254, that is,

- CDN$26 * 10 = CDN$ 260 because of the 10 large boxes plus

- CDN$ 4 *2= CDN$ 8 because of the 2 small boxes

- minus CDN$ 2 * 7 = CDN$6 (because of the seven unused chocolates).

Notice that the company may have a net loss, when there are not enough chocolates to create any package.

For example:
choco(7) should return '0..0..7..-14'

As an example, the following code fragment:

print (choco(503))

should produce the output:

10..2..7..254

python

Answer 1

Code:-

def choco(n): #function
largecount=0
smallcount=0
while(True): #loop
if n>=48: #if n is greater than or equal to 48
largecount+=1 #increment count
n=n-48 #decreasing n value
elif n>=8: #if n is greater than or equal to 8
smallcount+=1 #increment count
n=n-8 #decreasing n value
else:
break #breaking the loop
unused=n #unused is remaining n value
net = 26*largecount + 4*smallcount - 2*unused #calculating net value
out=str(largecount)+".."+str(smallcount)+".."+str(unused)+".."+str(net) #format
return out #return string out
n=int(input("Enter n: "))
print(choco(n)) #calling function
  

Screenshot:-

Output:-