An asteroid, whose mass is 2.50×10-4 times the mass of Earth, revolves in a circular orbit...
An asteroid, whose mass is 2.50×10-4 times the mass of Earth, revolves in a circular orbit around the Sun at a distance that is 2 times the Earth's distance from the Sun. Calculate the period of revolution of the asteroid.
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What is the ratio of the kinetic energy of the asteroid to the kinetic energy of Earth?
Homework Answers
We use the law of periods,
T² = (4π²/GM)r³
where M is the mass of the sun and r is the radius of the
orbit.kinetic energy of any asteroid or planet in a circular orbit
of radius r is given by K = GMm/2r, where m is the mass of the
asteroid or planet. As kinetic energy is proportional to m and
inversely proportional to r.
there E is the subscript for the dimensions related to the earth.
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