What will be the Kp for the following equilibrium: Cl2(l)→Cl2(g)
Select the correct answer below:
Kp=PCl2(g)PCl2(l)
Kp=PCl2(g)
Kp=1PCl2(g)
Kp=PCl2(l)
What will be the Kp for the following equilibrium: Cl2(l)→Cl2(g) Select the correct answer below: Kp=PCl2(g)PCl2(l)...
1. The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) <----> PCl3(g) + Cl2(g) Calculate the equilibrium partial pressures of all species when PCl5(g) is introduced into an evacuated flask at a pressure of 1.00 atm at 500 K. PPCl5 = atm PPCl3 = atm PCl2 = atm 2. The equilibrium constant, Kp, for the following reaction is 0.215 at 673 K: NH4I(s) <----> NH3(g) + HI(g) Calculate the equilibrium partial pressure of HI when...
A-The following reaction has a Kp=1.6 x 104 at 1500 K. CH4(g) + Cl2(g) CH3Cl(g) + HCl(g) a. In a reaction mixture, PCH4 = 0.13atm , PCl2 = 0.035atm , PCH3Cl = 0.24atm , and PHCl = 0.47atm . Is the system at equilibrium? If not how does the reaction proceed to reach equilibrium? At equilibrium, the following stresses are applied. How is the equilibrium affected? Explain. i. HCl is removed. ii. CH3Cl is added iii. The volume is reduced...
Consider the following reaction: I2(g)+Cl2(g)⇌2ICl(g), Kp=81.9 (at 25∘C) A reaction mixture at 25∘C initially contains PI2 = 0.110 atm , PCl2 = 0.110 atm , and PICl = 0.00 atm. Find the equilibrium partial pressure of I2 at this temperature. Find the equilibrium partial pressure of Cl2 at this temperature. Find the equilibrium partial pressure of ICl at this temperature.
The equilibrium constant, Kp, for the following reaction is 1.57 at 600 K: CO(g) + Cl2(g) COCl2(g) Calculate the equilibrium partial pressures of all species when CO and Cl2, each at an intitial partial pressure of 1.70 atm, are introduced into an evacuated vessel at 600 K. PCO = atm PCl2 = atm PCOCl2 = atm B. The equilibrium constant, Kc, for the following reaction is 2.90×10-2 at 1150 K. 2SO3(g) 2SO2(g) + O2(g) Calculate Kc at this temperature for...
Consider the following reaction: I2(g)+Cl2(g) ⇌ 2ICl(g) Kp= 81.9 at 25 ∘ C. Calculate ΔGrxn for the reaction at 25 ∘ C under each of the following conditions. Part A. Standard conditions Part B. At equilibrium Part C. PICl= 2.59 atm PI2= 0.322 atm PCl2= 0.221 atm
The equilibrium partial pressures for the reaction Cl2 (g) + PCl3 (g) ↔ PCl5 (g) at 300 K are PCl2 = 0.75 atm, PPCl3 = 0.45 atm, and PPCl5 = 0.73 atm. The value of Kp is __________. A. 0.15 B. 0.048 C. 4.7 D. 2.16
Consider the following reaction: I2(g)+Cl2(g) ⇌ 2ICl(g) Kp= 81.9 at 25 ∘ C. Calculate ΔGrxn for the reaction at 25 ∘ C under each of the following conditions. PICl= 2.58 atm PI2= 0.322 atm PCl2= 0.214 atm Express your answer using one significant figure.
Consider the following reaction: I2(g)+Cl2(g) ⇌ 2ICl(g) Kp= 81.9 at 25 ∘ C. Calculate ΔGrxn for the reaction at 25 ∘ C under each of the following conditions. PICl= 2.58 atm ; PI2= 0.324 atm ; PCl2= 0.221 atm . Express your answer using one significant figure.
At 400K, the equilibrium constant for the reaction Br2(g) + Cl2(g) ⇌ 2BrCl(g) is KP = 7.0. A closed vessel at 400K is charged with 1.00 atm of Br2(g), 1.00 atm of Cl2(g), and 2.00 atm of BrCl(g). Use Q to determine which of the statements below is true. A. The equilibrium partial pressure of BrCl(g) will be less than 2.00 atm B. The reaction will go to completion since there are equal amounts of Br2 and Cl2 C. At...
I2(g)+Cl2(g)⇌2ICl(g),Kp=81.9 (at 25∘C) The reaction between I2 and Cl2 is carried out at the same temperature, but with the following initial partial pressures: PI2=0.170atm, PCl2=0.170atm, and PICl=0.00 atm. find equibilibrum partial pressure of ICl.