6. The ozone content in polluted air can be determined by an iodometric titration. The air sample is bubbled through a buffered KI solution at a rate of 2.8 L/min for 1.5 hr. The density of the air sample is 1.17 g/L. The ozone is reduced by the iodide in the solution according to the following reaction.
O3 g+3 I- aq+2 H+ aq → O2 g+ I3- aq+H2O l
The resulting I3– is titrated with 0.00265 M Na2S2O3 requiring 9.84 mL to reach the endpoint.
2 S2O32- aq+I3- aq → S4O62- aq+3 I- aq
Determine the ozone content of the air sample in ppm (mg O3/kg air). (5 pts)
6. The ozone content in polluted air can be determined by an iodometric titration. The air...
A sample of copper ore with a mass of 0.4225 g was dissolved in acid. A solution of potassium iodide was added, which caused the reaction: 2Cu2+(aq) + 5I– (aq) → I3–(aq ) + 2CuI(s) The I3– that formed reacted quantitatively with exactly 29.96 mL of 0.02100 M Na2S2O3 according to the following equation: I3– (aq) + 2S2O32– (aq) → 3I– (aq ) + S4O62–(aq ) What was the percentage by mass of copper in the ore? If the ore...
The cation content of a water sample is determined by exchanging the cations for protons on strong acid and ion-exchange resin. An 25 mL sample was added to a 2 g resin. After reaching equilibrium the resin is filtered off and the solution titrated with alkali. 18 mL of 0.020 M NaOH are required to reach the endpoint. Calculate the normal concentration of cations ( the number of equivalents present in 1 L of sample).Your answer must be in order...
1. Moles of Reactant to Mass of Reactant: Identify the iodide ions and ozone in the balanced chemical equation. Use mole ratio, then convert to grams. A method used by the EPA for determining the ozone concentration in the air is to pass an air sample through a bubbler containing iodide ions. The iodide ions remove the ozone according to the following reaction: O3(g) + 2 I-(aq) + H2O(l) → O2(g) + I2(aq) + 2 OH-(aq) How many grams of ozone...
Q 1(a) [13.33 Marks] Levels of dissolved oxygen in water can be determined by the Winkler method in the Leaving Certificate Chemistry course as follows: Under alkaline conditions manganese(II) sulphate produces a white precipitate of manganese(II) hydroxide: Mn2+(aq) + 2OH-(aq) → Mn(OH)2(s) This reacts with the dissolved oxygen to produce a brown precipitate. 2Mn(OH)2(s) + O2(aq) → 2MnO(OH)2(s) Addition of concentrated H2SO4 releases free iodine from KI. MnO(OH)2(s) + 4H+(aq) + 21-(aq) + Mn2+(aq) + 12(aq) + 3H2O(1) The free...
Can you do number 3 Construct and calculate a theoretical titration curve, showing and discussing all key areas, for the titration of 0.100 M NaOH with 50.0 mL 0.100 M HNO_2 (K_aHNO_2 = 7.1 times 10^-4) A 30.0 L of air sample (Density of 1.20 g/L) was passed through an absorption tower containing a solution of Cd^2+, where H_2S was retained as CdS. The mixture was acidified and treated with 10.0 mL of 0.01070 M I_2. After the reaction S^2-_...