Question

A wastewater flow of 0.38m3/ min is highly acidic and requires neutralization prior to secondary treatment. This flow is to be neutralized to a pH of 7.0 using lime. As per laboratory titration results for the wastewater a two – stage control neutralization system will be required with a total commercial grade lime consumption of 2250 mg/L, consisting of 2000 mg/L in the first stage and 250 mg/L in the second stage. Calculate the volumes of the neutralization basins and power of the mixer’s motors at the rate of 40 W/m3 for a detention time of 5 min.

Answer 1

waste water is to be neutralized as to have PH value 7 , so in order to that we need a neutralizing basin.

Volume of neutralising basin will be dependent of detention time and flow rate of waste water.

So lets solve it.

Given that flow of waste water = 0.38 m3/min.

Detention time in the neutralizing basin = 5min

Hence volume of the neutralising basin required = 0.38*5 = 1.9 m3

Hence volume of the neutralising basin required = 0.38*5 = 1.9 m3

Now power requirement is given as 40 W/m3

Hence total power requirement =40*1.9 = 76 Watt.

Total power requirement =40*1.9 = 76 Watt.

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