2) The plates of a parallel-plate capacitor are 700cm2 in area and 0.3 cm apart. The...
2) The plates of a parallel-plate capacitor are 700cm2 in area and 0.3 cm apart. The potential difference between the plates is 935 V. (a) What is the magnitude of the electric field between the plates? (b) the charge on each plate? (c) the force exerted by the field on one of the plates? Now the two plates touch at the bot- tom forming a V-shape. (d) Find the total electric energy stored between the plates.
In d) is U=0J? Because from what I understand is when the two plates are TOUCHING, this creates a short circuit because the distance between the plates becomes ZERO. so the electrons move directly with no obstacle turning the potential energy to ZERO.
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2) The plates of a parallel-plate capacitor are 700cm2 in area
and 0.3 cm apart. The...
The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The...
The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The potential difference between the plates is 935 V. (a) What is the magnitude of the electric field between the plates? (b) the charge on each plate? (c) the force exerted by the field on one of the plates? Now the two plates touch at the bottom forming a V-shape. (d) Find the total electric energy stored between the plates.
1) The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart....
1) The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The potential difference between the plates is 935 V. (a) What is the magnitude of the electric field between the plates? (b) the charge on each plate? (c) the force exerted by the field on one of the plates? Now the two plates touch at the bottom forming a V-shape. (d) Find the total electric energy stored between the plates.
d and e 3. The plates of a parallel capacitor are 600 cm in are and...
d and e
3. The plates of a parallel capacitor are 600 cm in are and 0.2 cm apart. The po- tential difference between the plates is 800 V. (a) What is the electric field between the plates? (b) the charge on each plate? (c) the force exerted by the electric field on one of the plates? (d) Suppose that the plates are pulled apart so that the sep aration increases by 10 percent. What is the change in the...
A parallel-plate capacitor (Homework #2) A parallel-plate capacitor is made by a pair of plates with...
A parallel-plate capacitor (Homework #2) A parallel-plate capacitor is made by a pair of plates with area A and separation d. At first, the plates are charged up to +Q and -O respectively, and then a battery is disconnected. Express all the answers for a) through f) only by Q, d, A and 5 +Q 2d -Q Area A a) What is the electric field E inside of the capacitor? b) What is the potential difference V between the plates?...
5 A parallel-plate capacitor (Homework #2) A parallel-plate capacitor is made by a pair of plates...
5 A parallel-plate capacitor (Homework #2) A parallel-plate capacitor is made by a pair of plates with area A and separation d. At first, the plates are charged up to+ and - respectively, and then a battery is disconnected. Express all the answers for a) through f only by Q, d, A and s 2d Area A Now the places are pulled apart until the separation becomes 2d What is the electric field E'inside of the capacitor? (Express E" by...
The plates of a parallel-plate capacitor are 3.50 mm apart, and each carries a charge of...
The plates of a parallel-plate capacitor are 3.50 mm apart, and each carries a charge of magnitude 85.0 nC . The plates are in vacuum. The electric field between the plates has a magnitude of 5.00×106 V/m . Part A: What is the potential difference between the plates? Part B:What is the area of each plate? Part C:What is the capacitance?
A parallel-plate air capacitor is made by using two square plates, 13 cm × 13 cm...
A parallel-plate air capacitor is made by using two square plates, 13 cm × 13 cm each, spaced 3.7 mm apart. It is connected to a 10-V battery. If the capacitor remains connected to the battery and the plates are pulled apart to a separation of 7.7 mm . a) What is the new capacitance? b) What is the new charge on each plate? c)What is the new electric field between the plates? d) What is the new energy stored...
A parallel plate capacitor is constructed with circular plates of radius 0.750 cm and plate separation...
A parallel plate capacitor is constructed with circular plates of radius 0.750 cm and plate separation 0.0500 mm. If the capacitor is connected across a 37.2 V source, find: a) the capacitance b) the surface charge on each plate c) The energy stored in the capacitor d) the electric field between the plates e) the energy density between the plates
The parallel plates in a capacitor, with a plate area of 9.90 cm2 and an air-filled...
The parallel plates in a capacitor, with a plate area of 9.90 cm2 and an air-filled separation of 2.30 mm, are charged by a 4.10 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 6.50 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.
The parallel plates in a capacitor, with a plate area of 9.00 cm2 and an air-filled...
The parallel plates in a capacitor, with a plate area of 9.00 cm2 and an air-filled separation of 3.30 mm, are charged by a 5.40 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.10 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates
d and e
3. The plates of a parallel capacitor are 600 cm in are and 0.2 cm apart. The po- tential difference between the plates is 800 V. (a) What is the electric field between the plates? (b) the charge on each plate? (c) the force exerted by the electric field on one of the plates? (d) Suppose that the plates are pulled apart so that the sep aration increases by 10 percent. What is the change in the...
A parallel-plate capacitor (Homework #2) A parallel-plate capacitor is made by a pair of plates with area A and separation d. At first, the plates are charged up to +Q and -O respectively, and then a battery is disconnected. Express all the answers for a) through f) only by Q, d, A and 5 +Q 2d -Q Area A a) What is the electric field E inside of the capacitor? b) What is the potential difference V between the plates?...
5 A parallel-plate capacitor (Homework #2) A parallel-plate capacitor is made by a pair of plates with area A and separation d. At first, the plates are charged up to+ and - respectively, and then a battery is disconnected. Express all the answers for a) through f only by Q, d, A and s 2d Area A Now the places are pulled apart until the separation becomes 2d What is the electric field E'inside of the capacitor? (Express E" by...
The parallel plates in a capacitor, with a plate area of 9.90 cm2 and an air-filled separation of 2.30 mm, are charged by a 4.10 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 6.50 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.
The parallel plates in a capacitor, with a plate area of 9.00 cm2 and an air-filled separation of 3.30 mm, are charged by a 5.40 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.10 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates
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