Calculate the mass, in grams, of calcium acetate that must be added to a 500-mL volumetric...
Calculate the mass, in grams, of calcium acetate that must be added to a 500-mL volumetric flask in order to prepare 500 mL of a 0.238 M aqueous solution of the salt.
Homework Answers
Answer
18.823g
Explanation
Molarity = number of moles of solute per liter of solutions
0.238 M Ca(CH3COO)2 = 0.238mol Ca(CH3COO)2 per 500ml of solution
number of moles of Ca(CH3COO)2 required to 500ml of solution = 0.238mol/2 = 0.119mol
mass = number of moles × molar mass
mass of Ca(CH3COO)2 required =0.119mol × 158.18g/mol = 18.823g
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