Heights of men are normally distributed with a mean of 176 cm and a standard deviation...
Heights of men are normally distributed with a mean of 176 cm and a standard deviation of 7 cm. What is the approximate percentage of men greater than 155 cm?
Homework Answers
Solution :
Given that ,
mean = 
= 176
standard deviation = 
= 7
P(x > 155) = 1 - p( x< 155)
=1- p P[(x -
) /
< (155 - 176) / 7 ]
=1- P(z < -3)
Using z table,
= 1 - 0.0087
= 0.9987
The percentage is = 99.87%
Add Answer to:
Heights of men are normally distributed with a mean of 176 cm
and a standard deviation...
Heights of men are normally distributed with a mean of 69.0 inches and a standard deviation...
Heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. What is the probability that a randomly selected group of 16 men have a mean height greater than 71 inches.
Assume that the heights of men are normally distributed with a mean of 70.9 inches and a standard deviation of 2.1...
Assume that the heights of men are normally distributed with a mean of 70.9 inches and a standard deviation of 2.1 inches. If 36 men are randomly selected, find the probability that they have a mean height greater than 71.9 inches. 0.9979 0.0021 0.9005 0.0210
A survey found that women's heights are normally distributed with mean 62.4 in and standard deviation...
A survey found that women's heights are normally distributed with mean 62.4 in and standard deviation 2.1 in. The survey also found that men's heights are normally distributed with mean 68.5 in and standard deviation 3.1 in. Consider an executive jet that seats six with a doorway height of 55.6 in.a. What percentage of adult men can fit through the door without bending? The percentage of men who can fit without bending is
12A survey found that women's heights are normally distributed with mean 63.3 in. and standard deviation...
12A survey found that women's heights are normally distributed with mean 63.3 in. and standard deviation 2.3 in. The survey also found that men's heights are normally distributed with a mean 67.3 in. and standard deviation 92.9. Complete parts a through c below. The percentage of women who meet the height requirement is ____ Find the percentage of men meeting the height requirement. _____ If the height requirements are changed to exclude only the tallest 5% of men and the...
Assume that the heights of men are normally distributed with a mean of 67.9 inches and a...
Assume that the heights of men are normally distributed with a mean of 67.9 inches and a standard deviation of 2.1 inches. If 36 men are ramdomly selectd, find theprobability that they have a mean height greater than 68.9 inches.
Assume that the heights of men are normally distributed with a mean of 68.1 inches and...
Assume that the heights of men are normally distributed with a mean of 68.1 inches and a standard deviation of 2.8 inches. If 64 men are randomly selected, find the probability that they have a mean height greater than 69.1 inches
A survey found that women's heights are normally distributed with mean 63.1 in. and standard deviation...
A survey found that women's heights are normally distributed with mean 63.1 in. and standard deviation 3.5 in. The survey also found that men's heights are normally distributed with mean 67.4 in. and standard deviation 3.8 in. Consider an executive jet that seats six with a doorway height of 56.5 in. Complete parts (a) through (c) below. a. What percentage of adult men can fit through the door without bending? %. The percentage of men who can fit without bending...
A survey found that women's heights are normally distributed with mean 62.2 in. and standard deviation...
A survey found that women's heights are normally distributed with mean 62.2 in. and standard deviation 3.2 in. The survey also found that men's heights are normally distributed with mean 67.2 in. and standard deviation 3.5 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 55 in. and a maximum of 62 in. Complete parts (a) and (b) below what is The percentage of men who meet the height requirement? If...
A survey found that women's heights are normally distributed with mean 63.6 in and standard deviation...
A survey found that women's heights are normally distributed with mean 63.6 in and standard deviation 3.7 in. The survey also found that men's heights are normally distributed with mean of 69.9 in and standard deviation 3.7 in. Consider an executive jet that seats six with a doorway height of 56.3 in. Complete parts a through c below: a-What percentage of adult men can fit through the door without bending? - What doorway height would allow 40% of men to...
If it is assumed that the heights of men are normally distributed with a standard deviation...
If it is assumed that the heights of men are normally distributed with a standard deviation of 3.0 inches, how large a sample should be taken to be fairly sure (probability 0.95) that the sample mean does not differ from the true mean (population mean) by more than 0.20? (Give your answer as a whole number.) n ≥ _______
Assume that the heights of men are normally distributed with a mean of 70.9 inches and a standard deviation of 2.1 inches. If 36 men are randomly selected, find the probability that they have a mean height greater than 71.9 inches. 0.9979 0.0021 0.9005 0.0210
A survey found that women's heights are normally distributed with mean 63.1 in. and standard deviation 3.5 in. The survey also found that men's heights are normally distributed with mean 67.4 in. and standard deviation 3.8 in. Consider an executive jet that seats six with a doorway height of 56.5 in. Complete parts (a) through (c) below. a. What percentage of adult men can fit through the door without bending? %. The percentage of men who can fit without bending...
Most questions answered within 3 hours.
-
Find a map online of major or minor tectonic plates, and choose
one of interest to...
asked 4 minutes ago -
5. Explain why direct antigen activation of CTLs and B cells is
more important than APC-initiated...
asked 10 minutes ago -
Seaborgium (Z= 106) can be synthesized by the bombardment of
249Cf with 16O. If four (4)...
asked 17 minutes ago -
acorn holdings, a Uk company is entering into a long term
agreement with Ahmed Habib Textiles,...
asked 15 minutes ago -
A methodology to help create stability in a process is
Wh
Question 11 options:
Daily meetings...
asked 16 minutes ago -
Km = {(Vmax([S]))/(V)} – [S]
• Vmax = 100 (units)
• At [S] = 20 M...
asked 17 minutes ago -
Suggest a way to distinguish Citrobacter freundii from
Escherichia coli and from Proteus species.
asked 32 minutes ago -
Compute the IRR static for Project E. The appropriate
cost of capital is 9 percent. 0...
asked 1 hour ago -
The distribution of a test's scores for college-bound male
seniors has a mean of 1523 and...
asked 1 hour ago -
Valiant Industries has 30 million shares of stock outstanding at
a price of $25.44 per share....
asked 1 hour ago -
I need help with my javascript project, I've started on it but I
can't seem to...
asked 2 hours ago -
Identification of unknown Bacteria by sequencing
rDNA
Having a little trouble understanding the PCR process. This...
asked 3 hours ago