25)Example 20 A manufacturer has 600 litres of a 12% solution of acid. How many litres
of a 30% acid solution must be added to it so that acid content in the resulting mixture
will be more than 15% but less than 18%?
Solution Let x litres of 30%o acid solution is required to be added. Then
Total mixture = (x + 600) litres
Therefore 30%x+ 12% of 600 > 15% of (x+ 600)
And 30% x + 12% of 600 < 18% of (x + 600).
or30x/100+12/100(600)>15/100(x+600)
And 30x/100+12/100(600)<18/100(x+600)
or 30x + 7200 > 15x+ 9000
and 30x + 7200 < 18x+ 10800
Or 15x> 1800 and 12x < 3600
Or X> 120 and x < 300,
ie.
120
25)Example 20 A manufacturer has 600 litres of a 12% solution of acid. How many litres of a 30% acid solution must be added to it so that acid content in the resulting mixture will be more than 15% but less than 18%?
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