⦁ (12 pts) Calcium carbide, CaC2, reacts with water to form calcium hydroxide and the flammable gas acetylene, C2H2. (Historically, this reaction was used for bicycle lamps and miner’s helmets!) When 96.5 g of calcium carbide was reacted with 52.3 g of water according to the reaction below, 99.3 g of calcium hydroxide was produced. What was the percent yield of this reaction?
CaC2 + 2H2O Ca(OH)2 + C2H2
Moles of CaC2 = mass / molar mass
= 96.5 / 64
= 1.51 moles
Moles of water = 52.3 / 18
= 2.91
CaC2 + 2H2O = Ca(OH)2 + C2H2
Now 1 mole CaC2 require 2 mole H2O
1.51 mole will require = 1.51 * 2 = 3.02 mole
But we have only 2.91 mole H2O
So H2O is limiting reagent
Now mole of Ca(OH)2 = 1/2 mole of H2O
= 1/2 * 2.91
= 1.455
Mass of Ca(OH)2
= Mole * molar mass
= 1.455 * 74
= 107.67 grams
% yield = ( oberserved mass / calculated mass )*100
= (99.3 / 107.67 )*100
= 92.23 %
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⦁ (12 pts) Calcium carbide, CaC2, reacts with water to form calcium hydroxide and the flammable...
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