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A 120-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m...

A 120-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.700 rev/s in 2.00 s? (State the magnitude of the force.)
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Answer #1

Then w = w0 + alpha t

Then expression for the torque is

z=I alpha

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