ZuoTi.Pro
Question

A parallel plate capacitor is initially filled with air. A potential difference V0 is produced between...

A parallel plate capacitor is initially filled with air. A potential difference V0 is produced between the plates and then the power supply is disconnected. After the power supply is disconnected a dielectric of dielectric constant k is inserted between the plates. What is the new voltage Vf between the plates? Group of answer choices

Vf = V0 / k

Vf = kV0

Vf = (1/2)(k + 1)V0

Vf = V0

science   physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

0 0
Add a comment
Know the answer?
Add Answer to:
A parallel plate capacitor is initially filled with air. A potential difference V0 is produced between...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a...

    The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a separation of 8.80 mm are charged to a 130-V potential difference. After the plates are disconnected from the source, a porcelain dielectric with κ = 6.5 is inserted between the plates of the capacitor. (a) What is the charge on the capacitor before and after the dielectric is inserted? Qi = ___C Qf = ____C (b) What is the capacitance of the capacitor after...

  • A parallel-plate capacitor filled with air carries a charge Q. The battery is disconnected, and a...

    A parallel-plate capacitor filled with air carries a charge Q. The battery is disconnected, and a slab of material with dielectric constant k = 2 is inserted between the plates. Which of the following statements is correct? The voltage across the capacitor decreases by a factor of 2. The voltage across the capacitor is doubled.       The electric field is doubled. The charge on the plates decreases by a factor of 2. The charge on the plates is doubled.

  • A 193 volt battery is connected to a 0.3 microfarad parallel-plate capacitor with air between the...

    A 193 volt battery is connected to a 0.3 microfarad parallel-plate capacitor with air between the plates. Now the battery is disconnected, with care taken not to discharge the capacitor. Some paper is then inserted between the plates completely filling up the space. What is the final potential difference between the plates ? (the dielectric constant for air is = 1 and for the paper inserted is = 3)

  • An air-filled parallel-plate capacitor has plate area A andplate separation d. The capacitor is connected...

    An air-filled parallel-plate capacitor has plate area A and plate separation d. The capacitor is connected to a battery that creates a constant voltage V.A) Find the energy U_0 stored in the capacitor. Express your answer in terms of A, d, V, and ϵ_0.B) The capacitor is now disconnected from the battery, and the plates of the capacitor are then slowly pulled apart until the separation reaches 3d. Find the new energy U_1 of the capacitor after this process. Express...

  • A 50 pF parallel-plate capacitor with an air gap between the plates is connected to a...

    A 50 pF parallel-plate capacitor with an air gap between the plates is connected to a 50V battery. A Teflon (K=2) slab is then inserted between the plates and completely fills the gap. Then the battery is disconnected. What is the new potential difference? (1 pF = 10-12 F)

  • A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of...

    A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of d = 2.00 mm. The capacitor is charged to a potential difference of V0 = 150 V by a battery. A dielectric sheet (κ = 3.50) of the same area but thickness ℓ = 1.00 mm is placed between the plates without disconnecting the battery. (See figure 24-18 on page 642). Determine the initial capacitance of the air-filled capacitor. Determine the charge on the...

  • A 2.0 μF parallel-plate air-filled capacitor is connected across a 10 V battery. (a) Determine the...

    A 2.0 μF parallel-plate air-filled capacitor is connected across a 10 V battery. (a) Determine the charge on the capacitor and the energy stored in the capacitor. (b) An identical 2.0 μF parallel-plate air-filled capacitor is connected across a 5 V battery, and a dielectric slab with dielectric constant κ is inserted between the plates of the capacitor, completely filling the region between the plates, while the battery remains connected. The energy stored in this capacitor is four times that...

  • A 50 pF parallel-plate capacitor with an air gap between the plates is connected to a...

    A 50 pF parallel-plate capacitor with an air gap between the plates is connected to a 50V battery. A Teflon (K=2) slab is then inserted between the plates and completely fills the gap. Then the battery is disconnected. What is the new potential difference? (1 pF - 10-12 F) 50V 100V 25V 250V

  • A 50 pF parallel-plate capacitor with an air gap between the plates is connected to a...

    A 50 pF parallel-plate capacitor with an air gap between the plates is connected to a 50V battery. A Teflon (K=2) slab is then inserted between the plates and completely fills the gap. Then the battery is disconnected. What is the new potential difference? (1 pF = 10-12 F) 250V 50V 25V 100V

  • An air-filled parallel plate capacitor with a plate spacing of 1.20 cm has a capacitance of...

    An air-filled parallel plate capacitor with a plate spacing of 1.20 cm has a capacitance of 3.40 �F. The plate spacing is now doubled and a dielectric is inserted, completely filling the space between the plates. As a result the capcitance becomes 15.4 �F. Calculate the dielectric constant of the inserted material.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT